4x^2+14x-17=0

Solution for 4x^2+14x-17=0 equation:

4x^2+14x-17=0

a = 4; b = 14; c = -17;
Δ = b2-4ac
Δ = 142-4·4·(-17)
Δ = 468
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{468}=\sqrt{36*13}=\sqrt{36}*\sqrt{13}=6\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-6\sqrt{13}}{2*4}=\frac{-14-6\sqrt{13}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+6\sqrt{13}}{2*4}=\frac{-14+6\sqrt{13}}{8}
$